56x-48x^2=0

Solution for 56x-48x^2=0 equation:

56x-48x^2=0

a = -48; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·(-48)·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*-48}=\frac{-112}{-96}
=1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*-48}=\frac{0}{-96}
=0
$